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Class 9th Mathematics Chapter 11 Circles – Important Questions

Important questions with answers for Class 9th Mathematics Chapter 11 Circles, based on the NCERT CBSE syllabus.

Topics covered in Circles

Frequently asked questions

Where can I find important questions for Class 9th Mathematics Chapter 11 Circles?

This page lists important questions with answers for Circles. Topics covered: Chord and arc, Angle subtended by chord, Perpendicular from centre, Cyclic quadrilateral, Equal chords.

Are Circles important questions free?

Yes, Notebook gives free NCERT CBSE important questions for Class 9 Mathematics.

How to prepare Circles for Class 9 Mathematics exams?

Read the Circles notes first, revise the key topics (Chord and arc, Angle subtended by chord, Perpendicular from centre, Cyclic quadrilateral, Equal chords), then practise the important questions and previous year questions (PYQ) for this chapter.

Where can I find Class 9th Mathematics Chapter 11 Circles important questions for quick revision?

You are on the right page: this important questions page for Circles covers Class 9 Mathematics for the CBSE exam 2026-27. Use the tabs on this chapter for notes, important questions and PYQ.

Is Class 9th Mathematics Chapter 11 Circles important for the CBSE exam 2026-27?

Circles is part of the Class 9 Mathematics NCERT CBSE syllabus. Notebook gives notes, important questions and PYQs for it, free.

Also see: Class 9th Mathematics Chapter 11 Circles Notes · Class 9th Mathematics Chapter 11 Circles PYQ

Circles

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1 Mark
What is the curved surface area of a cylinder of radius r and height h?
Ans: CSA of cylinder = 2πrh.
2 Marks
Find the volume of a cone with radius 7 cm and height 24 cm. (π = 22/7)
Ans: l = √(7²+24²) = √(49+576) = √625 = 25 cm. Volume = ⅓πr²h = ⅓ × 22/7 × 49 × 24 = ⅓ × 22 × 7 × 24 = 1232 cm³.
3 Marks
The radius of a sphere is 6 cm. Find its surface area and volume. (π = 3.14)
Ans: Surface area = 4πr² = 4 × 3.14 × 36 = 452.16 cm². Volume = (4/3)πr³ = (4/3) × 3.14 × 216 = 904.32 cm³.
5 Marks
A cylindrical tank has radius 7 m and height 10 m. Find: (a) TSA (b) Volume (c) Cost of painting the curved surface at ₹50/m². (π = 22/7)
Ans: (a) TSA = 2πr(r+h) = 2×22/7×7×(7+10) = 44×17 = 748 m². (b) Volume = πr²h = 22/7×49×10 = 1540 m³. (c) CSA = 2πrh = 2×22/7×7×10 = 440 m². Cost = 440×50 = ₹22,000.
Other chapters in Mathematics · Class 9 View all Mathematics chapters →
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