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Class 10th Mathematics Chapter 5 Arithmetic Progressions – Important Questions

Important questions with answers for Class 10th Mathematics Chapter 5 Arithmetic Progressions, based on the NCERT CBSE syllabus.

Topics covered in Arithmetic Progressions

Frequently asked questions

Where can I find important questions for Class 10th Mathematics Chapter 5 Arithmetic Progressions?

This page lists important questions with answers for Arithmetic Progressions. Topics covered: Definition of AP, Common difference, General term (nth term), Sum of first n terms.

Are Arithmetic Progressions important questions free?

Yes, Notebook gives free NCERT CBSE important questions for Class 10 Mathematics.

How to prepare Arithmetic Progressions for Class 10 Mathematics exams?

Read the Arithmetic Progressions notes first, revise the key topics (Definition of AP, Common difference, General term (nth term), Sum of first n terms), then practise the important questions and previous year questions (PYQ) for this chapter.

Where can I find Class 10th Mathematics Chapter 5 Arithmetic Progressions important questions for quick revision?

You are on the right page: this important questions page for Arithmetic Progressions covers Class 10 Mathematics for the CBSE exam 2026-27. Use the tabs on this chapter for notes, important questions and PYQ.

Is Class 10th Mathematics Chapter 5 Arithmetic Progressions important for the CBSE exam 2026-27?

Arithmetic Progressions is part of the Class 10 Mathematics NCERT CBSE syllabus. Notebook gives notes, important questions and PYQs for it, free.

Also see: Class 10th Mathematics Chapter 5 Arithmetic Progressions Notes · Class 10th Mathematics Chapter 5 Arithmetic Progressions PYQ

Arithmetic Progressions

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1 Mark
What is the common difference of the AP: 3, 1, –1, –3?
Ans: Common difference d = 1 – 3 = –2.
2 Marks
Find the 20th term of the AP: 2, 7, 12, 17…
Ans: a = 2, d = 5. a₂₀ = 2 + (20–1)×5 = 2 + 95 = 97.
3 Marks
Find the sum of first 24 terms of the AP: 5, 8, 11, 14…
Ans: a = 5, d = 3. S₂₄ = 24/2 × [2×5 + 23×3] = 12 × [10 + 69] = 12 × 79 = 948.
5 Marks
The sum of first 7 terms of an AP is 49 and sum of first 17 terms is 289. Find the AP.
Ans: S₇ = 49 → 7/2(2a+6d) = 49 → 2a+6d = 14 → a+3d = 7. S₁₇ = 289 → 17/2(2a+16d) = 289 → a+8d = 17. Subtracting: 5d = 10 → d = 2, a = 1. AP: 1, 3, 5, 7, 9…
Other chapters in Mathematics · Class 10 View all Mathematics chapters →
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