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Class 10th Mathematics Chapter 8 Introduction to Trigonometry – PYQ

Previous year questions (PYQ) with answers for Class 10th Mathematics Chapter 8 Introduction to Trigonometry, based on the NCERT CBSE syllabus.

Topics covered in Introduction to Trigonometry

Frequently asked questions

Where can I find previous year questions (PYQ) for Class 10th Mathematics Chapter 8 Introduction to Trigonometry?

This page lists previous year questions with answers for Introduction to Trigonometry. Topics covered: Trigonometric ratios, Trigonometric identities, Values at standard angles, Complementary angles.

Are Introduction to Trigonometry PYQs free?

Yes, Notebook gives free previous year questions for Class 10 Mathematics.

How to prepare Introduction to Trigonometry for Class 10 Mathematics exams?

Read the Introduction to Trigonometry notes first, revise the key topics (Trigonometric ratios, Trigonometric identities, Values at standard angles, Complementary angles), then practise the important questions and previous year questions (PYQ) for this chapter.

Where can I find Class 10th Mathematics Chapter 8 Introduction to Trigonometry pyq for quick revision?

You are on the right page: this pyq page for Introduction to Trigonometry covers Class 10 Mathematics for the CBSE exam 2026-27. Use the tabs on this chapter for notes, important questions and PYQ.

Is Class 10th Mathematics Chapter 8 Introduction to Trigonometry important for the CBSE exam 2026-27?

Introduction to Trigonometry is part of the Class 10 Mathematics NCERT CBSE syllabus. Notebook gives notes, important questions and PYQs for it, free.

Also see: Class 10th Mathematics Chapter 8 Introduction to Trigonometry Notes · Class 10th Mathematics Chapter 8 Introduction to Trigonometry Important Questions

Introduction to Trigonometry

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3 Marks 2023
If sin A = 3/5, find cos A and tan A.
Ans: sin A = 3/5 → opposite = 3, hypotenuse = 5, adjacent = 4. cos A = 4/5, tan A = 3/4.
2 Marks 2022
Prove that sin²θ + cos²θ = 1.
Ans: In right triangle: sin θ = opposite/hypotenuse, cos θ = adjacent/hypotenuse. sin²θ + cos²θ = (opp² + adj²)/hyp² = hyp²/hyp² = 1. (By Pythagoras theorem).
5 Marks 2019
Prove that (tan A + sin A)/(tan A - sin A) = (sec A + 1)/(sec A - 1).
Ans: LHS = (sin A/cos A + sin A)/(sin A/cos A - sin A) = sin A(1+cos A) / sin A(1-cos A) / cos A... simplifies to (1+cos A)/(1-cos A) = (sec A+1)/(sec A-1) = RHS.
Other chapters in Mathematics · Class 10 View all Mathematics chapters →
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