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Class 10th Mathematics Chapter 11 Areas Related to Circles – Important Questions

Important questions with answers for Class 10th Mathematics Chapter 11 Areas Related to Circles, based on the NCERT CBSE syllabus.

Topics covered in Areas Related to Circles

Frequently asked questions

Where can I find important questions for Class 10th Mathematics Chapter 11 Areas Related to Circles?

This page lists important questions with answers for Areas Related to Circles. Topics covered: Area and perimeter of sector, Area of segment, Combinations with triangles and rectangles.

Are Areas Related to Circles important questions free?

Yes, Notebook gives free NCERT CBSE important questions for Class 10 Mathematics.

How to prepare Areas Related to Circles for Class 10 Mathematics exams?

Read the Areas Related to Circles notes first, revise the key topics (Area and perimeter of sector, Area of segment, Combinations with triangles and rectangles), then practise the important questions and previous year questions (PYQ) for this chapter.

Where can I find Class 10th Mathematics Chapter 11 Areas Related to Circles important questions for quick revision?

You are on the right page: this important questions page for Areas Related to Circles covers Class 10 Mathematics for the CBSE exam 2026-27. Use the tabs on this chapter for notes, important questions and PYQ.

Is Class 10th Mathematics Chapter 11 Areas Related to Circles important for the CBSE exam 2026-27?

Areas Related to Circles is part of the Class 10 Mathematics NCERT CBSE syllabus. Notebook gives notes, important questions and PYQs for it, free.

Also see: Class 10th Mathematics Chapter 11 Areas Related to Circles Notes · Class 10th Mathematics Chapter 11 Areas Related to Circles PYQ

Areas Related to Circles

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3 Marks
Find the area of a sector of a circle with radius 7 cm and angle 90°.
Ans: Area of sector = (θ/360°) × πr² = (90/360) × (22/7) × 49 = ¼ × 154 = 38.5 cm².
3 Marks
Find the area of a minor segment of a circle with radius 14 cm and central angle 60°.
Ans: Area of sector = (60/360) × π × 196 = 102.67 cm². Area of triangle = (√3/4) × 14² = 84.87 cm². Area of segment = 102.67 − 84.87 = 17.8 cm².
2 Marks
What is the area of a ring with outer radius 10 cm and inner radius 6 cm?
Ans: Area = π(R² − r²) = π(100 − 36) = 64π ≈ 201.1 cm².
Other chapters in Mathematics · Class 10 View all Mathematics chapters →
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