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Class 10th Science Chapter 4 Carbon and its Compounds – Important Questions

Important questions with answers for Class 10th Science Chapter 4 Carbon and its Compounds, based on the NCERT CBSE syllabus.

Topics covered in Carbon and its Compounds

Frequently asked questions

Where can I find important questions for Class 10th Science Chapter 4 Carbon and its Compounds?

This page lists important questions with answers for Carbon and its Compounds. Topics covered: Covalent bonding, Allotropes of carbon, IUPAC nomenclature, Hydrocarbons, Ethanol, Ethanoic acid, Soaps and detergents.

Are Carbon and its Compounds important questions free?

Yes, Notebook gives free NCERT CBSE important questions for Class 10 Science.

How to prepare Carbon and its Compounds for Class 10 Science exams?

Read the Carbon and its Compounds notes first, revise the key topics (Covalent bonding, Allotropes of carbon, IUPAC nomenclature, Hydrocarbons, Ethanol, Ethanoic acid, Soaps and detergents), then practise the important questions and previous year questions (PYQ) for this chapter.

Where can I find Class 10th Science Chapter 4 Carbon and its Compounds important questions for quick revision?

You are on the right page: this important questions page for Carbon and its Compounds covers Class 10 Science for the CBSE exam 2026-27. Use the tabs on this chapter for notes, important questions and PYQ.

Is Class 10th Science Chapter 4 Carbon and its Compounds important for the CBSE exam 2026-27?

Carbon and its Compounds is part of the Class 10 Science NCERT CBSE syllabus. Notebook gives notes, important questions and PYQs for it, free.

Also see: Class 10th Science Chapter 4 Carbon and its Compounds Notes · Class 10th Science Chapter 4 Carbon and its Compounds PYQ

Carbon and its Compounds

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1 Mark
What is the valency of carbon?
Ans: The valency of carbon is 4.
1 Mark
Name two allotropes of carbon.
Ans: Diamond and Graphite are two allotropes of carbon.
3 Marks
What are saturated and unsaturated hydrocarbons? Give one example each.
Ans: Saturated hydrocarbons have only single C–C bonds (alkanes). Example: Ethane (C₂H₆). Unsaturated hydrocarbons have double or triple C–C bonds. Example: Ethene (C₂H₄) — double bond; Ethyne (C₂H₂) — triple bond.
3 Marks
How do soaps clean oily dirt? Explain the role of micelles.
Ans: Soap molecules have a hydrophilic head (attracts water) and hydrophobic tail (repels water, attracts oil). In water, tails surround oil droplets while heads face outward, forming micelles. These micelles keep oil suspended in water and are washed away.
5 Marks
Explain homologous series with properties and give examples for alkanes, alkenes, alkynes.
Ans: A homologous series is a group of organic compounds with same functional group, differing by –CH₂– unit and 14 mass units. They show gradual change in physical properties. Alkanes: CH₄, C₂H₆, C₃H₈ (CₙH₂ₙ₊₂). Alkenes: C₂H₄, C₃H₆ (CₙH₂ₙ). Alkynes: C₂H₂, C₃H₄ (CₙH₂ₙ₋₂). Functional groups determine chemical behaviour.
2 Mark
Why does carbon form a large number of compounds compared to other elements?
Ans: Carbon forms an extremely large number of compounds due to two unique properties: (1) Catenation: Carbon atoms can bond with other carbon atoms to form long chains, branched chains, and ring (cyclic) structures. No other element shows this property to such an extent. (2) Tetravalency: Carbon has 4 valence electrons and can form 4 covalent bonds — with hydrogen, oxygen, nitrogen, sulphur, halogens, and other carbon atoms — giving rise to millions of stable compounds (the basis of organic chemistry).
3 Mark
What are homologous series? State four characteristics with an example.
Ans: A homologous series is a series of organic compounds with the same functional group and similar chemical properties, where each successive member differs by a –CH₂– unit (14 u) in molecular mass. Example: Alkanes — CH₄, C₂H₆, C₃H₈, C₄H₁₀... Characteristics: (1) Same general formula (alkanes: CₙH₂ₙ₊₂). (2) Same functional group → similar chemical properties. (3) Physical properties (BP, MP, density) change gradually with increasing carbon chain length. (4) Each member is called a homologue; consecutive members differ by 14 u. (5) Can be prepared by similar methods. Example: Alcohols: CH₃OH, C₂H₅OH, C₃H₇OH... (–OH group, formula CₙH₂ₙ₊₂O).
3 Mark
Explain esterification and saponification with reactions.
Ans: Esterification: Reaction between a carboxylic acid and an alcohol in the presence of an acid catalyst (conc. H₂SO₄) and heat to form an ester and water. CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O (ethyl ethanoate/ethyl acetate). Esters have a sweet fruity smell — used in perfumes, flavouring agents, solvents. Saponification: Hydrolysis of an ester using a base (NaOH) to give back the alcohol and sodium salt of the acid (soap). CH₃COOC₂H₅ + NaOH → CH₃COONa + C₂H₅OH. On a larger scale: Fat + NaOH → Soap + Glycerol. This is how soaps are manufactured (alkaline hydrolysis of fats/oils).
2 Mark
Distinguish between diamond and graphite as allotropes of carbon.
Ans: Diamond: Each C is bonded to 4 other C atoms in a 3D tetrahedral structure. Hardest natural substance. Does not conduct electricity (no free electrons). Very high MP. Used in cutting tools, jewellery. Graphite: Each C is bonded to 3 other C atoms in flat hexagonal layers. Soft and slippery (layers slide). Conducts electricity (1 free electron per C). Used as lubricant, pencil leads, electrodes. Key difference: Diamond (sp³ hybridisation, no free electrons) vs Graphite (sp² hybridisation, delocalised electrons in each layer).
2 Mark
Why does soap not work in hard water? What is used instead?
Ans: Hard water contains Ca²⁺ and Mg²⁺ ions. Soap (sodium stearate, C₁₇H₃₅COONa) reacts with these ions to form insoluble calcium/magnesium salts (scum): 2C₁₇H₃₅COONa + CaCl₂ → (C₁₇H₃₅COO)₂Ca↓ + 2NaCl. This white scum is deposited on clothes and wastes soap — no lather forms until all Ca²⁺/Mg²⁺ are precipitated. Solution: Detergents are used instead. Detergents have a sulphonate group (–SO₃Na) instead of carboxylate — their calcium and magnesium salts are soluble, so they work in hard water.
1 Mark
What is catenation?
Ans: Catenation is the property of an element to form bonds with its own atoms, giving long chains, branched chains and rings. Carbon shows catenation to the maximum extent.
1 Mark
Write the molecular formula and name of the third member of the alkane series.
Ans: The third member of the alkane series is propane, C₃H₈ (after methane CH₄ and ethane C₂H₆).
1 Mark
Name the functional groups present in CH₃COOH and CH₃CHO.
Ans: CH₃COOH contains the carboxylic acid group (–COOH). CH₃CHO contains the aldehyde group (–CHO).
2 Mark
Draw the electron dot structure of methane and state the number of covalent bonds.
Ans: In methane (CH₄) carbon (2, 4) shares each of its four valence electrons with one hydrogen atom, and each hydrogen shares its one electron with carbon. Thus carbon forms four single covalent bonds with four hydrogen atoms, and each atom gets a stable configuration (carbon an octet, hydrogen a duplet).
2 Mark
Why are carbon compounds generally poor conductors of electricity?
Ans: Carbon compounds are formed by covalent bonds, in which electrons are shared and not transferred. No ions are formed, so there are no free charged particles to carry current.
2 Mark
How would you distinguish chemically between ethanol and ethanoic acid?
Ans: Add sodium hydrogencarbonate (or sodium carbonate) to each. Ethanoic acid gives brisk effervescence of CO₂, which turns lime water milky; ethanol does not. Ethanoic acid also turns blue litmus red, while ethanol is neutral to litmus.
3 Mark
Write the IUPAC names of: (a) CH₃CH₂CH₂OH, (b) CH₃CH₂CHO, (c) CH₃COCH₃, (d) CH₃CH₂COOH, (e) CH₃CH=CH₂.
Ans: (a) Propan-1-ol (propanol). (b) Propanal. (c) Propanone. (d) Propanoic acid. (e) Propene.
3 Mark
What is hydrogenation? Give an equation and one industrial use.
Ans: Hydrogenation is the addition of hydrogen to unsaturated hydrocarbons in the presence of a catalyst such as nickel or palladium to give saturated compounds: CH₂=CH₂ + H₂ → CH₃–CH₃ (Ni catalyst). It is used industrially to convert vegetable oils (unsaturated) into solid saturated fats such as vanaspati ghee.
5 Mark
Describe the chemical properties of carbon compounds: combustion, oxidation, addition and substitution reactions, with equations.
Ans: Combustion: CH₄ + 2O₂ → CO₂ + 2H₂O + heat and light; saturated compounds burn with a blue flame, unsaturated with a sooty yellow flame. Oxidation: alcohol is oxidised to carboxylic acid with alkaline KMnO₄ or acidified K₂Cr₂O₇: CH₃CH₂OH → CH₃COOH. Addition: unsaturated hydrocarbons add hydrogen in the presence of Ni: CH₂=CH₂ + H₂ → CH₃CH₃. Substitution: in sunlight, a hydrogen atom of a saturated hydrocarbon is replaced: CH₄ + Cl₂ → CH₃Cl + HCl.
5 Mark
Write the reactions of ethanol with sodium and with concentrated sulphuric acid at 443 K. State two uses and two harmful effects of ethanol.
Ans: With sodium: 2CH₃CH₂OH + 2Na → 2CH₃CH₂ONa + H₂ (sodium ethoxide and hydrogen gas). With hot conc. H₂SO₄ at 443 K (dehydration): CH₃CH₂OH → CH₂=CH₂ + H₂O (ethene). Uses: as a solvent for medicines, tinctures and cough syrups; as a fuel additive (power alcohol). Harmful effects: drinking it affects the nervous system, causes addiction and liver damage; pure methanol is poisonous and can cause blindness or death, so industrial alcohol is denatured.
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