1 Mark
State the Law of Conservation of Mass.
Ans: The Law of Conservation of Mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. Mass is neither created nor destroyed during a chemical reaction. (Given by Antoine Lavoisier, 1789.)
1 Mark
What is an atom? What is the SI unit of atomic mass?
Ans: An atom is the smallest particle of an element that can take part in a chemical reaction. It may or may not exist independently. The SI unit of atomic mass is unified atomic mass unit (u), where 1u = 1/12 the mass of one atom of carbon-12 = 1.66 × 10⁻²⁴ g.
2 Mark
State the Law of Constant Proportions and give an example.
Ans: Law of Constant Proportions (Proust's Law): In a pure chemical compound, elements are always present in definite proportions by mass. Example: Water (H₂O) always contains H and O in mass ratio 1:8 regardless of its source. CO₂ always has C:O in ratio 3:8. This law shows that compounds have a fixed, definite composition.
2 Mark
What is a mole? What is Avogadro's number?
Ans: A mole is defined as the amount of a substance that contains as many elementary entities (atoms, molecules, ions) as there are atoms in exactly 12 g of carbon-12. This number is called Avogadro's number (Nₐ) = 6.022 × 10²³. So 1 mole of any substance contains 6.022 × 10²³ entities. Molar mass = atomic/molecular mass expressed in grams = mass of 1 mole of the substance.
2 Mark
What is the difference between an atom and a molecule?
Ans: Atom: Smallest particle of an element; may not exist independently (e.g., Na, O); has atomic mass. Molecule: Smallest particle of a substance (element or compound) that can exist independently; formed by combination of two or more atoms; has molecular mass = sum of atomic masses. Examples: O₂, N₂, H₂O, CO₂. Diatomic molecules: H₂, O₂, N₂, F₂, Cl₂, Br₂, I₂. Monoatomic molecules: Noble gases (He, Ne, Ar).
3 Mark
Write the formulae of the following and calculate their molecular masses: (a) Water, (b) Carbon dioxide, (c) Glucose, (d) Sulphuric acid.
Ans: (a) Water: H₂O. Mol. mass = 2(1) + 16 = 18 u. (b) Carbon dioxide: CO₂. Mol. mass = 12 + 2(16) = 44 u. (c) Glucose: C₆H₁₂O₆. Mol. mass = 6(12) + 12(1) + 6(16) = 72 + 12 + 96 = 180 u. (d) Sulphuric acid: H₂SO₄. Mol. mass = 2(1) + 32 + 4(16) = 2 + 32 + 64 = 98 u. Atomic masses used: H=1, C=12, N=14, O=16, S=32, Na=23, Cl=35.5.
3 Mark
What are polyatomic ions? Give 5 examples with their formulae and charges.
Ans: Polyatomic ions are groups of atoms carrying a net electric charge, that act as a single unit in a compound. Examples: (1) Ammonium ion: NH₄⁺ (+1). (2) Hydroxide ion: OH⁻ (–1). (3) Carbonate ion: CO₃²⁻ (–2). (4) Sulphate ion: SO₄²⁻ (–2). (5) Nitrate ion: NO₃⁻ (–1). (6) Phosphate ion: PO₄³⁻ (–3). (7) Bicarbonate/Hydrogen carbonate: HCO₃⁻ (–1). These ions do not exist independently — they are found in ionic compounds such as Na₂CO₃, (NH₄)₂SO₄ etc.
5 Mark
Calculate: (a) Number of moles in 46 g of Na, (b) Mass of 2 moles of CO₂, (c) Number of molecules in 9 g of water, (d) Number of atoms in 0.5 mole of O₂.
Ans: (a) Molar mass of Na = 23 g/mol. Moles = 46/23 = 2 moles. (b) Molar mass of CO₂ = 44 g/mol. Mass = 2 × 44 = 88 g. (c) Molar mass of H₂O = 18 g/mol. Moles = 9/18 = 0.5 moles. Molecules = 0.5 × 6.022 × 10²³ = 3.011 × 10²³ molecules. (d) Moles of O₂ = 0.5. Each O₂ has 2 atoms. Atoms = 0.5 × 2 × 6.022 × 10²³ = 6.022 × 10²³ atoms. Key formulae: Moles = Given mass/Molar mass; Number of particles = Moles × Nₐ; Molar mass = sum of atomic masses in grams.
2 Mark
How do you write the formula of an ionic compound? Write the formula of calcium phosphate.
Ans: Formula writing rule: Write the symbols of the ions with their valencies (charges). Cross-multiply the valencies (use criss-cross method) to get the subscripts. Simplify if possible. Calcium ion: Ca²⁺; Phosphate ion: PO₄³⁻. Cross-multiplying: Ca₃(PO₄)₂. Formula of calcium phosphate = Ca₃(PO₄)₂. Other examples: AlCl₃ (Al³⁺, Cl⁻); Na₂SO₄ (Na⁺, SO₄²⁻); MgO (Mg²⁺, O²⁻).
1 Mark
What is the atomicity of ozone, phosphorus and sulphur?
Ans: Atomicity is the number of atoms in one molecule of an element. Ozone (O₃): atomicity = 3. Phosphorus (P₄): atomicity = 4. Sulphur (S₈): atomicity = 8. Noble gases (He, Ne, Ar): atomicity = 1 (monoatomic). O₂, N₂, H₂: atomicity = 2 (diatomic).
1 Mark
Define molecular mass.
Ans: Molecular mass of a substance is the sum of the atomic masses of all the atoms in a molecule of the substance. It is expressed in atomic mass units (u). Example: H₂O = 2 × 1 + 16 = 18 u.
1 Mark
What is meant by formula unit mass?
Ans: Formula unit mass is the sum of the atomic masses of all the atoms in a formula unit of an ionic compound, expressed in u. Example: NaCl = 23 + 35.5 = 58.5 u.
1 Mark
Calculate the molecular mass of HNO₃. (H = 1, N = 14, O = 16)
Ans: Molecular mass of HNO₃ = 1 + 14 + (3 × 16) = 1 + 14 + 48 = 63 u.
2 Mark
Calculate the number of moles and the number of atoms in 52 g of helium (He = 4 u).
Ans: Moles = 52 ÷ 4 = 13 mol. Helium is monoatomic, so number of atoms = 13 × 6.022 × 10²³ = 7.83 × 10²⁴ atoms.
2 Mark
What is an ion? Differentiate between a cation and an anion with one example each.
Ans: An ion is a charged particle formed when an atom or group of atoms gains or loses electrons. A cation is a positively charged ion formed by loss of electrons, e.g. Na⁺. An anion is a negatively charged ion formed by gain of electrons, e.g. Cl⁻.
2 Mark
What is the ratio by mass of hydrogen and oxygen in water? Which law of chemical combination does it illustrate?
Ans: In water (H₂O), hydrogen and oxygen are always combined in the ratio 1 : 8 by mass (2 g of hydrogen to 16 g of oxygen). Water from any source has this same ratio, which illustrates the Law of Constant Proportions (Proust).
3 Mark
A sample of vitamin C contains 2.58 × 10²⁴ oxygen atoms. How many moles of oxygen atoms are present?
Ans: Moles = number of atoms ÷ Avogadro's number = 2.58 × 10²⁴ ÷ 6.022 × 10²³ = 4.28 mol. So the sample contains about 4.28 moles of oxygen atoms.
5 Mark
Calculate: (a) the mass of 0.5 mole of N₂, (b) the number of molecules in 0.5 mole of N₂, (c) the number of moles in 9 g of H₂O, (d) the number of atoms in 9 g of H₂O. (N = 14, H = 1, O = 16)
Ans: (a) Molar mass of N₂ = 28 g/mol, so mass = 0.5 × 28 = 14 g. (b) Molecules = 0.5 × 6.022 × 10²³ = 3.011 × 10²³. (c) Molar mass of H₂O = 18 g/mol, so moles = 9 ÷ 18 = 0.5 mol. (d) Molecules of H₂O = 0.5 × 6.022 × 10²³ = 3.011 × 10²³; each molecule has 3 atoms, so atoms = 3 × 3.011 × 10²³ = 9.033 × 10²³.
3 Mark
When 5.3 g of sodium carbonate reacts with 6 g of ethanoic acid, 2.2 g of carbon dioxide, 8.2 g of sodium ethanoate and 0.9 g of water are produced. Show that these observations agree with the law of conservation of mass.
Ans: Mass of reactants = 5.3 + 6.0 = 11.3 g. Mass of products = 2.2 + 8.2 + 0.9 = 11.3 g. Since the total mass of reactants equals the total mass of products, mass is neither created nor destroyed in the reaction. This verifies the Law of Conservation of Mass (Lavoisier).
5 Mark
State the postulates of Dalton's atomic theory. Mention its limitations.
Ans: Postulates: (1) All matter is made of extremely small indivisible particles called atoms. (2) Atoms of a given element are identical in mass and properties. (3) Atoms of different elements have different masses and properties. (4) Atoms combine in small whole-number ratios to form compounds. (5) Atoms are neither created nor destroyed in a chemical reaction. Limitations: atoms are divisible into protons, neutrons and electrons; atoms of the same element can have different masses (isotopes); atoms of different elements can have the same mass (isobars).