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Class 9th Science Chapter 7 Atoms and Molecules – Important Questions

Important questions with answers for Class 9th Science Chapter 7 Atoms and Molecules, based on the NCERT CBSE syllabus.

Topics covered in Atoms and Molecules

Frequently asked questions

Where can I find important questions for Class 9th Science Chapter 7 Atoms and Molecules?

This page lists important questions with answers for Atoms and Molecules. Topics covered: Law of conservation of mass, Law of constant proportions, Dalton's atomic theory, Atomic mass, Molecular mass, Mole concept, Avogadro's number.

Are Atoms and Molecules important questions free?

Yes, Notebook gives free NCERT CBSE important questions for Class 9 Science.

How to prepare Atoms and Molecules for Class 9 Science exams?

Read the Atoms and Molecules notes first, revise the key topics (Law of conservation of mass, Law of constant proportions, Dalton's atomic theory, Atomic mass, Molecular mass, Mole concept, Avogadro's number), then practise the important questions and previous year questions (PYQ) for this chapter.

Where can I find Class 9th Science Chapter 7 Atoms and Molecules important questions for quick revision?

You are on the right page: this important questions page for Atoms and Molecules covers Class 9 Science for the CBSE exam 2026-27. Use the tabs on this chapter for notes, important questions and PYQ.

Is Class 9th Science Chapter 7 Atoms and Molecules important for the CBSE exam 2026-27?

Atoms and Molecules is part of the Class 9 Science NCERT CBSE syllabus. Notebook gives notes, important questions and PYQs for it, free.

Also see: Class 9th Science Chapter 7 Atoms and Molecules Notes · Class 9th Science Chapter 7 Atoms and Molecules PYQ

Atoms and Molecules

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1 Mark
State the Law of Conservation of Mass.
Ans: The Law of Conservation of Mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. Mass is neither created nor destroyed during a chemical reaction. (Given by Antoine Lavoisier, 1789.)
1 Mark
What is an atom? What is the SI unit of atomic mass?
Ans: An atom is the smallest particle of an element that can take part in a chemical reaction. It may or may not exist independently. The SI unit of atomic mass is unified atomic mass unit (u), where 1u = 1/12 the mass of one atom of carbon-12 = 1.66 × 10⁻²⁴ g.
2 Mark
State the Law of Constant Proportions and give an example.
Ans: Law of Constant Proportions (Proust's Law): In a pure chemical compound, elements are always present in definite proportions by mass. Example: Water (H₂O) always contains H and O in mass ratio 1:8 regardless of its source. CO₂ always has C:O in ratio 3:8. This law shows that compounds have a fixed, definite composition.
2 Mark
What is a mole? What is Avogadro's number?
Ans: A mole is defined as the amount of a substance that contains as many elementary entities (atoms, molecules, ions) as there are atoms in exactly 12 g of carbon-12. This number is called Avogadro's number (Nₐ) = 6.022 × 10²³. So 1 mole of any substance contains 6.022 × 10²³ entities. Molar mass = atomic/molecular mass expressed in grams = mass of 1 mole of the substance.
2 Mark
What is the difference between an atom and a molecule?
Ans: Atom: Smallest particle of an element; may not exist independently (e.g., Na, O); has atomic mass. Molecule: Smallest particle of a substance (element or compound) that can exist independently; formed by combination of two or more atoms; has molecular mass = sum of atomic masses. Examples: O₂, N₂, H₂O, CO₂. Diatomic molecules: H₂, O₂, N₂, F₂, Cl₂, Br₂, I₂. Monoatomic molecules: Noble gases (He, Ne, Ar).
3 Mark
Write the formulae of the following and calculate their molecular masses: (a) Water, (b) Carbon dioxide, (c) Glucose, (d) Sulphuric acid.
Ans: (a) Water: H₂O. Mol. mass = 2(1) + 16 = 18 u. (b) Carbon dioxide: CO₂. Mol. mass = 12 + 2(16) = 44 u. (c) Glucose: C₆H₁₂O₆. Mol. mass = 6(12) + 12(1) + 6(16) = 72 + 12 + 96 = 180 u. (d) Sulphuric acid: H₂SO₄. Mol. mass = 2(1) + 32 + 4(16) = 2 + 32 + 64 = 98 u. Atomic masses used: H=1, C=12, N=14, O=16, S=32, Na=23, Cl=35.5.
3 Mark
What are polyatomic ions? Give 5 examples with their formulae and charges.
Ans: Polyatomic ions are groups of atoms carrying a net electric charge, that act as a single unit in a compound. Examples: (1) Ammonium ion: NH₄⁺ (+1). (2) Hydroxide ion: OH⁻ (–1). (3) Carbonate ion: CO₃²⁻ (–2). (4) Sulphate ion: SO₄²⁻ (–2). (5) Nitrate ion: NO₃⁻ (–1). (6) Phosphate ion: PO₄³⁻ (–3). (7) Bicarbonate/Hydrogen carbonate: HCO₃⁻ (–1). These ions do not exist independently — they are found in ionic compounds such as Na₂CO₃, (NH₄)₂SO₄ etc.
5 Mark
Calculate: (a) Number of moles in 46 g of Na, (b) Mass of 2 moles of CO₂, (c) Number of molecules in 9 g of water, (d) Number of atoms in 0.5 mole of O₂.
Ans: (a) Molar mass of Na = 23 g/mol. Moles = 46/23 = 2 moles. (b) Molar mass of CO₂ = 44 g/mol. Mass = 2 × 44 = 88 g. (c) Molar mass of H₂O = 18 g/mol. Moles = 9/18 = 0.5 moles. Molecules = 0.5 × 6.022 × 10²³ = 3.011 × 10²³ molecules. (d) Moles of O₂ = 0.5. Each O₂ has 2 atoms. Atoms = 0.5 × 2 × 6.022 × 10²³ = 6.022 × 10²³ atoms. Key formulae: Moles = Given mass/Molar mass; Number of particles = Moles × Nₐ; Molar mass = sum of atomic masses in grams.
2 Mark
How do you write the formula of an ionic compound? Write the formula of calcium phosphate.
Ans: Formula writing rule: Write the symbols of the ions with their valencies (charges). Cross-multiply the valencies (use criss-cross method) to get the subscripts. Simplify if possible. Calcium ion: Ca²⁺; Phosphate ion: PO₄³⁻. Cross-multiplying: Ca₃(PO₄)₂. Formula of calcium phosphate = Ca₃(PO₄)₂. Other examples: AlCl₃ (Al³⁺, Cl⁻); Na₂SO₄ (Na⁺, SO₄²⁻); MgO (Mg²⁺, O²⁻).
1 Mark
What is the atomicity of ozone, phosphorus and sulphur?
Ans: Atomicity is the number of atoms in one molecule of an element. Ozone (O₃): atomicity = 3. Phosphorus (P₄): atomicity = 4. Sulphur (S₈): atomicity = 8. Noble gases (He, Ne, Ar): atomicity = 1 (monoatomic). O₂, N₂, H₂: atomicity = 2 (diatomic).
1 Mark
Define molecular mass.
Ans: Molecular mass of a substance is the sum of the atomic masses of all the atoms in a molecule of the substance. It is expressed in atomic mass units (u). Example: H₂O = 2 × 1 + 16 = 18 u.
1 Mark
What is meant by formula unit mass?
Ans: Formula unit mass is the sum of the atomic masses of all the atoms in a formula unit of an ionic compound, expressed in u. Example: NaCl = 23 + 35.5 = 58.5 u.
1 Mark
Calculate the molecular mass of HNO₃. (H = 1, N = 14, O = 16)
Ans: Molecular mass of HNO₃ = 1 + 14 + (3 × 16) = 1 + 14 + 48 = 63 u.
2 Mark
Calculate the number of moles and the number of atoms in 52 g of helium (He = 4 u).
Ans: Moles = 52 ÷ 4 = 13 mol. Helium is monoatomic, so number of atoms = 13 × 6.022 × 10²³ = 7.83 × 10²⁴ atoms.
2 Mark
What is an ion? Differentiate between a cation and an anion with one example each.
Ans: An ion is a charged particle formed when an atom or group of atoms gains or loses electrons. A cation is a positively charged ion formed by loss of electrons, e.g. Na⁺. An anion is a negatively charged ion formed by gain of electrons, e.g. Cl⁻.
2 Mark
What is the ratio by mass of hydrogen and oxygen in water? Which law of chemical combination does it illustrate?
Ans: In water (H₂O), hydrogen and oxygen are always combined in the ratio 1 : 8 by mass (2 g of hydrogen to 16 g of oxygen). Water from any source has this same ratio, which illustrates the Law of Constant Proportions (Proust).
3 Mark
A sample of vitamin C contains 2.58 × 10²⁴ oxygen atoms. How many moles of oxygen atoms are present?
Ans: Moles = number of atoms ÷ Avogadro's number = 2.58 × 10²⁴ ÷ 6.022 × 10²³ = 4.28 mol. So the sample contains about 4.28 moles of oxygen atoms.
5 Mark
Calculate: (a) the mass of 0.5 mole of N₂, (b) the number of molecules in 0.5 mole of N₂, (c) the number of moles in 9 g of H₂O, (d) the number of atoms in 9 g of H₂O. (N = 14, H = 1, O = 16)
Ans: (a) Molar mass of N₂ = 28 g/mol, so mass = 0.5 × 28 = 14 g. (b) Molecules = 0.5 × 6.022 × 10²³ = 3.011 × 10²³. (c) Molar mass of H₂O = 18 g/mol, so moles = 9 ÷ 18 = 0.5 mol. (d) Molecules of H₂O = 0.5 × 6.022 × 10²³ = 3.011 × 10²³; each molecule has 3 atoms, so atoms = 3 × 3.011 × 10²³ = 9.033 × 10²³.
3 Mark
When 5.3 g of sodium carbonate reacts with 6 g of ethanoic acid, 2.2 g of carbon dioxide, 8.2 g of sodium ethanoate and 0.9 g of water are produced. Show that these observations agree with the law of conservation of mass.
Ans: Mass of reactants = 5.3 + 6.0 = 11.3 g. Mass of products = 2.2 + 8.2 + 0.9 = 11.3 g. Since the total mass of reactants equals the total mass of products, mass is neither created nor destroyed in the reaction. This verifies the Law of Conservation of Mass (Lavoisier).
5 Mark
State the postulates of Dalton's atomic theory. Mention its limitations.
Ans: Postulates: (1) All matter is made of extremely small indivisible particles called atoms. (2) Atoms of a given element are identical in mass and properties. (3) Atoms of different elements have different masses and properties. (4) Atoms combine in small whole-number ratios to form compounds. (5) Atoms are neither created nor destroyed in a chemical reaction. Limitations: atoms are divisible into protons, neutrons and electrons; atoms of the same element can have different masses (isotopes); atoms of different elements can have the same mass (isobars).
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